Let x be True & 0 be False. 
A : 2 Liars out of ABCDE 
B : C = 0 
C : 2 Liars out of ABDE 
D : E = 0 
E : 3 Liars out of ABCDE 
(A & E) and (D & E) are dependent,so... 
it\'d be easier to start from Andy,Danny or Eddie. 
Starting with Andy: 
IF(A=0) 
THEN 
E=x; 
D=0; 
{ 
IF(B=x THEN C=0) 
IF (B=0 THEN C=x) 
} 
where B=x may be True because when C is a Liar, \"2 Liars of ABDE\" may be False which is TRUE!  
Clearly, B=0 cant be TRUE. 
 
IF(A=x); 
//results will be opposite// 
D=x; 
E=0; 
B=0; //B=x is False for A=x// 
C=x; 
Sooo,... 
0x00x OR x0xx0 fits the answer for ABCDE where 0 are Liars. 
 
And something about Connie\'s statement: 
If its like,\"Im not the Liar but 2 of them are...\" 
Then, Babs and Danny can be trusted.  
Orrr 
If its,\"Im a Liar and 2 of them are also Liars...\" 
Then, Andy, Connie and Danny can be trusted. 
Wait. . .! 
...If a Liar says,\"Im a Liar\" isnt that a good reason to trust him or her? 
...unless  
if its a lie, told by speaking the truth..  
 
. . .like captain Jack Sparrow... 
LoL 
 
x_O